Intimate use mode

All exam materials in C9020-461 learning materials contain PDF, APP, and PC formats. They have the same questions and answers but with different using methods. If you like to take notes randomly according to your own habits while studying, we recommend that you use the PDF format. You can print all the materials in C9020-461 study engine to paper. Then you can sketch on the paper and mark the focus with different colored pens. This will be helpful for you to review the content of the materials. If you are busy with work and can't afford a lot of spare time to review, C9020-461 exam questions also prepare an APP version for you. The APP version provide you with mock exams, time-limited exams, and online error correction and let you can review on any electronic device. At the same time, for any version, we do not limit the number of downloads and the number of concurrent users, you can even buy C9020-461 learning materials together with your friends, which undoubtedly saves you a lot of overhead.

Advanced learning system

C9020-461 learning materials have a variety of self-learning and self-assessment functions to test learning outcomes. C9020-461 learning material is like a tutor, not only gives you a lot of knowledge, but also gives you a new set of learning methods. C9020-461 learning material is also equipped with a simulated examination system that simulates the real exam environment so that you can check your progress at any time. At the same time, C9020-461 study material also has a timekeeping function that allows you to be cautious and keep your own speed while you are practicing, so as to avoid the situation that you can't finish all the questions during the exam. With C9020-461 learning materials, you only need to spend half your money to get several times better service than others.

Free trial downloading before purchase

C9020-461 study engine is very attentive to provide a demo for all customers who concerned about our products, whose purpose is to allow customers to understand our product content and how to use the software before buying. Many students suspect that if C9020-461 learning material is really so magical? Does it really take only 20-30 hours to pass such a difficult certification exam successfully? It is no exaggeration to say that if you purchase C9020-461 exam questions and review it as required, you will be able to successfully pass the exam. And if you still don't believe what we are saying, you can log on our platform right now and get a trial version of C9020-461 study engine for free to experience the magic of it. Of course, if you encounter any problems during free trialing, feel free to contact us and we will help you to solve all problems.

As a wise person, it is better to choose our C9020-461 study material without any doubts. Due to the high quality and C9020-461 accurate questions & answers, many people have passed their actual test with the help of our products. Now, quickly download C9020-461 free demo for try. You will get 100% pass with our verified C9020-461 training guide.

DOWNLOAD DEMO

IBM C9020-461 Exam Syllabus Topics:

IBM Midrange Storage Technical Support V4 Sample Questions:

Question 1

What is IBM Security Key Lifecycle Manager used for?

A. To eliminate the requirement for encryption keys on managed devices
B. To activate encryption keys on USB drives for IBM Storwize V7000
C. To provide encryption for SAN attached storage devices
D. To control the access of encrypted storage devices

Question 2

A customer provides the information shown in the exhibit for the company's primary database environment. Solution requirements include meeting of exceeding the current I/O rate of the existing environment.
System name Name Max IOPS Avg IOPS Min IOPS Max BW (MBps) Avg BW (MBps) Min BW (MBps) Max Latency (ms) Avg Latency (ms) pldenxivg3 denoubivs_arch1 1101 20 0 274 5 0 3 2 pldenxivg3 denoubivs_arch2 3 0 0 0 0 0 0 0 pldenxivg3 denoubivs_bin1 322 1 0 1 0 0 32 0 pldenxivg3 denoubivs_bin2 184 0 0 1 0 0 21 0 pldenxivg3 denoubivs_bkup1 2 0 0 0 0 0 0 0 pldenxivg3 denoubivs_bkup2 25 0 0 2 0 0 0 0 pldenxivg3 denoubivs_bkup3 1 0 0 0 0 0 0 0 pldenxivg3 denoubivs_data1 997 39 0 128 3 0 28 2 pldenxivg3 denoubivs_data2 997 38 0 133 3 0 31 2 pldenxivg3 denoubivs_data3 1005 43 0 127 3 0 23 1 pldenxivg3 denoubivs_data4 2217 38 0 175 3 0 19 2 pldenxivg3 denoubivs_data5 1194 37 0 109 2 0 32 1 pldenxivg3 denoubivs_data6 1118 30 0 70 2 0 23 1 pldenxivg3 denoubivs_data7 1111 29 0 70 2 0 21 1 pldenxivg3 denoubivs_data8 2443 24 0 156 1 0 10 0 pldenxivg3 denoubivs_data9 1710 8 0 108 0 0 12 1 pldenxivg3 denoubivs_log1 2107 49 0 46 1 0 2 0 pldenxivg3 denoubivs_log2 2174 44 0 43 1 0 2 0 pldenxivg3 denoubivs_NJP_bin 8 0 0 0 0 0 0 0 pldenxivg3 denoubivs_NJP_data 1452 9 0 93 0 0 0 0 pldenxivg3 denoubivs_NJP_log 65 14 0 3 0 0 0 0 pldenxivg3 denoubivs_os1 16 0 0 0 0 0 0 0 pldenxivg3 denoubivs_os2 0 0 0 0 0 0 0 0 pldenxivg3 denoubivs_pg1 12 0 0 1 0 0 0 0 pldenxivg3 denoubivs_pg2 0 0 0 0 0 0 0 0 pldenxivg3 denoubivs_arch1 501 5 0 122 1 0 3 1 pldenxivg3 denoubivs_arch2 0 0 0 0 0 0 0 0 pldenxivg3 denoubivs_back1 1 0 0 0 0 0 0 0 pldenxivg3 denoubivs_back2 0 0 0 0 0 0 0 0 pldenxivg3 denoubivs_back3 2 0 0 0 0 0 0 0 pldenxivg3 denoubivs_bin1 209 2 0 6 0 0 16 0 pldenxivg3 denoubivs_bin2 283 0 0 17 0 0 18 1 pldenxivg3 denoubivs_bin3 176 1 0 8 0 0 18 1 pldenxivg3 denoubivs_data1 3128 116 0 201 5 0 17 0 pldenxivg3 denoubivs_data2 1117 65 0 71 2 0 16 0 pldenxivg3 denoubivs_data3 1129 69 0 71 2 0 16 0 pldenxivg3 denoubivs_data4 1136 63 0 72 2 0 16 0 pldenxivg3 denoubivs_data5 1147 65 0 72 2 0 16 0 pldenxivg3 denoubivs_data6 3470 60 0 223 2 0 36 0 pldenxivg3 denoubivs_data7 2389 51 0 152 2 0 20 0 pldenxivg3 denoubivs_log1 204 12 0 13 0 0 2 0 pldenxivg3 denoubivs_log2 279 11 0 12 0 0 3 0 pldenxivg3 denoubivs_os1 21 0 0 0 0 0 0 0 pldenxivg3 denoubivs_os2 0 0 0 0 0 0 0 0 pldenxivg3 denoubivs_pg1 2 0 0 0 0 0 0 0
Total= 35458 943 0 2580 44
Average= 788 21 0 57 1 0 10
0
What should the minimum I/O rate be for the new solution?

A. 21 I/Os per second
B. 943 I/Os per second
C. 35458 I/Os per second
D. 788 I/Os per second

Question 3

A customer is discussing the purchase of an IBM Storwize V7000 storage system and needs to decide which pre-set RAID algorithm to use. The customer is aware of an option called "Balance RAID 10" and has askedfor a description of how it functions.
What are the characteristics of this RAID type?

A. Data is mirrored on two array members and across two enclosure drive channels.
B. Data and one stripe of parity are striped across all array members.
C. Data on all drives in the array use the same drive channel wherever possible.
D. Data and two stripe of parity are striped across all array members.

Question 4

A customer is considering the costs of a storage system and is most concerned about the overall cost over the system's lifecycle.
Which cost factor should be considered?

A. ROI (Return on Investment)
B. CAPEX (Capital expenditure)
C. TCO (Total Cost of Ownership)
D. OPEX (Operating expense)

Question 5

Which IBM storage solution provides a powerful hardware platform with compression that can support the massive volumes of data created by today's demanding cloud and analytics applications?

A. IBM FlashSystem 840
B. IBM DCS3700
C. IBM Storwize V3700
D. IBM Storwize V7000

Solutions: